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Difficult Math Problem #17

This topic has 6 member replies
800guy Master | Next Rank: 500 Posts Default Avatar
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Difficult Math Problem #17

Post Wed Sep 20, 2006 4:58 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    OA coming after some people try answering..

    Matt starts a new job, with the goal of doubling his old average commission of $400. He takes a 10% commission, making commissions of $100.00, $200.00, $250.00, $700.00, and $1,000 on his first 5 sales. If Matt made two sales on the last day of the week, how much would Matt have had to sell in order to meet his goal?

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    gamemaster Senior | Next Rank: 100 Posts Default Avatar
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    Post Thu Sep 21, 2006 12:46 am
    if the average of 7 sales is 400$, than in total he had to earn 2800$ in 7 sales

    he made: 1000+700+250+200+100 = 2250$ in 5 sales

    so in the the last 2 sales he had to make a comission of 550$
    meaning he had to sell in an amount of 5500$

    r4rohini Newbie | Next Rank: 10 Posts Default Avatar
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    3 messages
    Post Thu Sep 21, 2006 1:14 am
    Hey!!! this is the way u do it :

    he wants to dowble his commission from $400 to $800

    100+200+250+700+1000+x+y
    ---------------------------------------- = 800
    7

    i.e 2250+x+y = 5600
    x+y = 3350

    Now he has to sell
    10/100 * z = 3350
    z= 33500

    He has to sell 33500 in order to double his average

    gamemaster Senior | Next Rank: 100 Posts Default Avatar
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    Post Thu Sep 21, 2006 1:27 am
    Yes

    i didnt notice they said 'doubled'

    but anyway, the method is the same ...

    jtsgmat Newbie | Next Rank: 10 Posts Default Avatar
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    Post Thu Sep 21, 2006 8:11 am
    The asnwer is correct if we assume that he sells during seven days. However, it could also be the case that there are only 5 days. Note that problem stated that he made five sales during the the week and 2 sales on the last day of the week.

    800guy Master | Next Rank: 500 Posts Default Avatar
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    Post Fri Sep 22, 2006 9:59 am
    here's the OA:

    The two sales on Matt's last day of the week must total $33,500.

    (100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
    x = 3350
    since x is Matt's 10% commission, the sale is $33,500.

    Post Sat Sep 23, 2017 1:07 pm
    Assuming the two sales on Matt's last day of the week must total $33,500.

    (100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
    2250+ x = 5600
    x= 5600-2250
    x = 3350
    since x which is the 10% Matt's commission, then the sale is $33,500.

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