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Register now and save up to $200 Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Free Trial & Practice Exam BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • Free Practice Test & Review How would you score if you took the GMAT Available with Beat the GMAT members only code • 1 Hour Free BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code ## Difficult Math Problem #17 This topic has 6 member replies 800guy Master | Next Rank: 500 Posts Joined 27 Jun 2006 Posted: 354 messages Followed by: 5 members Upvotes: 11 #### Difficult Math Problem #17 Wed Sep 20, 2006 4:58 pm OA coming after some people try answering.. Matt starts a new job, with the goal of doubling his old average commission of$400. He takes a 10% commission, making commissions of $100.00,$200.00, $250.00,$700.00, and $1,000 on his first 5 sales. If Matt made two sales on the last day of the week, how much would Matt have had to sell in order to meet his goal? Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums! 800guy Master | Next Rank: 500 Posts Joined 27 Jun 2006 Posted: 354 messages Followed by: 5 members Upvotes: 11 Top Reply Fri Sep 22, 2006 9:59 am here's the OA: The two sales on Matt's last day of the week must total$33,500.

(100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
x = 3350
since x is Matt's 10% commission, the sale is $33,500. ### Top Member Roland2rule Master | Next Rank: 500 Posts Joined 30 Aug 2017 Posted: 392 messages Followed by: 1 members Top Reply Sat Sep 23, 2017 1:07 pm Assuming the two sales on Matt's last day of the week must total$33,500.

(100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
2250+ x = 5600
x= 5600-2250
x = 3350
since x which is the 10% Matt's commission, then the sale is $33,500. 800guy Master | Next Rank: 500 Posts Joined 27 Jun 2006 Posted: 354 messages Followed by: 5 members Upvotes: 11 Fri Sep 22, 2006 9:59 am here's the OA: The two sales on Matt's last day of the week must total$33,500.

(100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
x = 3350
since x is Matt's 10% commission, the sale is $33,500. ### Top Member Roland2rule Master | Next Rank: 500 Posts Joined 30 Aug 2017 Posted: 392 messages Followed by: 1 members Sat Sep 23, 2017 1:07 pm Assuming the two sales on Matt's last day of the week must total$33,500.

(100 + 200 + 250 + 700 + 1000 + x) / 7 = 800
2250+ x = 5600
x= 5600-2250
x = 3350
since x which is the 10% Matt's commission, then the sale is \$33,500.

jtsgmat Newbie | Next Rank: 10 Posts
Joined
12 Jun 2006
Posted:
7 messages
Thu Sep 21, 2006 8:11 am
The asnwer is correct if we assume that he sells during seven days. However, it could also be the case that there are only 5 days. Note that problem stated that he made five sales during the the week and 2 sales on the last day of the week.

gamemaster Senior | Next Rank: 100 Posts
Joined
03 Sep 2006
Posted:
34 messages
Thu Sep 21, 2006 1:27 am
Yes

i didnt notice they said 'doubled'

but anyway, the method is the same ...

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