Hi,
Need help answering the question in the attached screen shot.
Thanks
Diameter of the circle
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The equilateral triangle cuts the circle in 3 equal arcs.Equilateral triangle ABC is inscribed in a circle (points ABC are on the circle). IF the length of arc ABC is 24, what is the approximate diameter of the circle
A) 5
B) 8
C) 11
D) 15
E) 19
Arc ABC travels the length of 2 of those arcs.
So, each arc must have length 12, which means the TOTAL CIRCUMFERENCE = (3)(12) = 36
Now, we'll use the formula: CIRCUMFERENCE = (pi)(diameter)
So, 36 = (3.14)(diameter)
This means that: diameter = 36/3.14
IMPORTANT: We need not perform any long division here. Notice that the answer choices are nicely spread apart. So, we can ESTIMATE.
We know that 36/3 = 12
Since 3.14 is a bit bigger than 3, we know that 36/3.14 will be a bit smaller than 12.
Answer choice C is a bit smaller than 12, so it must be the correct answer.
Cheers,
Brent
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A CENTRAL ANGLE is formed by two radii.Equilateral triangle ABC is inscribed in a circle (points ABC are on the circle). IF the length of arc ABC is 24, what is the approximate diameter of the circle
A) 5
B) 8
C) 11
D) 15
E) 19
An INSCRIBED ANGLE is formed by two chords.
When an inscribed angle and a central angle intercept the SAME ARC on a circle, the degree measurement of the inscribed angle is 1/2 the degree measurement of the central angle:
Circles display the following proportionality:
(Central Angle)/360 = (intercepted arc length)/circumference = (sector area)/(circle area)
Since 120/360 = 1/3, the intercepted arc in the circle above is 1/3 the circumference of the circle, and the sector enclosed by the two radii is 1/3 the area of the entire circle.
Onto the problem above:
Let c = circumference.
Since ∠A is 60º, the corresponding central angle = 120º.
Since 120/360 = 1/3, arc BC = (1/3)c.
Using similar logic, arc AB = (1/3)c.
Thus, arc ABC = (2/3)c.
Since arc ABC = 24, we get:
24 = 2/3c
c = 36.
Thus:
Ï€d = 36.
d ≈ 11.
The correct answer is C.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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