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## delivery cost

nafiul9090 Really wants to Beat The GMAT!
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delivery cost Tue Aug 14, 2012 8:44 pm
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• Lap #[LAPCOUNT] ([LAPTIME])
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niketdoshi123 Really wants to Beat The GMAT!
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Tue Aug 14, 2012 10:33 pm
nafiul9090 wrote:
You chose option D, so I assume that you know how statement 2 is sufficient to answer..

I'll prove how statement 1 is not sufficient
Question : was the total price of the merchandise in the two orders > \$499
Statement 1:
The delivery fee for one of the two orders was \$3.
The maximum order price for that order = \$100.

We don't know the delivery fee of the other order.
We will consider two extreme cases.

Min delivery fee that could be charged = \$3, for which the max order price would be \$100.

In this case the maximum total price of the two orders = \$100 + \$100 = \$200 < \$499 . Answer to the question "No"

Max delivery fee that could be charged = \$7, for which the min order price would be = \$500

In this case the maximum total price of the two orders = \$100 + \$500 = \$600 > \$499. Answer to the question "Yes".

Hence the statement is insufficient.

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Patrick_GMATFix GMAT Instructor
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Thu Aug 16, 2012 9:28 am
Statement 1:
To get a \$3 fee, the first order's price must have been between less than \$100. With no additional information, we can determine that (1) is insufficient since:

Scenario A: Order #1 has price \$1, delivery fee \$3. Order #2 has price \$1, delivery fee \$3.

Scenario B: Order #1 has price \$1, delivery fee \$3. Order #2 has price \$1,000, delivery fee \$7

Both scenarios respect the delivery cost schedule and statement (1). However while in Scenario A the sum of prices is tiny, in Scenario B the sum of prices is greater than \$499.

(1) is not sufficient.

Statement 2:
To determine sufficiency, do your best to answer the question in multiple ways without contradicting the statement. If multiple answers are achievable, you have insufficiency.

Scenario A: make the sum of prices large. The easiest way to get \$10 total delivery fee is to have one order with a \$3 fee and another with a \$7 fee. This will allow us to avoid that big nasty fraction. This is easy: Order #1 has price \$1, delivery fee \$3. Order #2 has price \$1,000 delivery fee \$7. Sum of fees is \$10 and sum of prices is greater than \$499.

Scenario B: make the sum of prices small (hopefully smaller than \$499). To make prices small while keeping delivery fees high (equal to \$10), need to take advantage of the first tier since for very low prices, delivery is expensive (relative to order price). So we could have order #1 price \$0.01 and delivery fee \$3. However to get to \$10 total delivery fee, we must either have a order #2 with price > 500 (delivery fee would be \$7 taking total delivery to \$10) or make Order #2 price = 500 (delivery fee from the middle tier would be 3+(500-100)/100 = \$7, taking total delivery to \$10). Either way, the total order price has to be greater than \$499.

(2) is sufficient.

B is correct.

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