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Co-ordinate Geometry Help!
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- theCodeToGMAT
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Is the Answer
(a) y = x --> (1,1), (2,2)
So contains
(b) y = x + 0.5 -> y - x = 0.5
Not possible
(c) y = x + 5 -> y - x = 5 --> (1,6) (2,7)
So contains
(d) y = 0.5x -> (2,1) (4,2)
So contains
(e) y = 0.5x + 5 -> (2,6) (4,7)
So contains
(a) y = x --> (1,1), (2,2)
So contains
(b) y = x + 0.5 -> y - x = 0.5
Not possible
(c) y = x + 5 -> y - x = 5 --> (1,6) (2,7)
So contains
(d) y = 0.5x -> (2,1) (4,2)
So contains
(e) y = 0.5x + 5 -> (2,6) (4,7)
So contains
R A H U L
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If a point (x,y) is on a given line, then the coordinates (x and y) of that point must satisfy the equation of that line.Which of the following lines in the xy-plane does not contain any point with integers as both coordinates?
A) y = x
B) y = x + 1/2
C) y = x + 5
D) y = (1/2)x
E) y = (1/2)x + 5
In answer choice B, the equation (y = x + 1/2) tells us that, for ANY POINT ON THE LINE, the y-coordinate will be equal to the x-coordinate plus 1/2
So, if the x-coordinate is an integer, the y-coordinate cannot be an integer.
So, it's impossible for any point on this line to have integers as both coordinates.
Answer: B
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We see that the point (1,1) is on the line y = x (answer choice A); (1, 6) on y = x + 5 (C); (2, 1) on y = x*1/2 (D); and (2, 6) on y = x/2 + 5 (E). Thus, the only line that won't have any point with integers as both coordinates is y = x + 1/2 (answer choice B). The reason is simple: if x is an integer, then y can't be an integer, since the sum of an integer and 1/2 will never be an integer. Similarly, if y is an integer, then x can't be an integer, since the difference of an integer and 1/2 (notice that x = y - 1/2) can never be an integer.vinay1983 wrote: Which of the following lines in the xy-plane does not contain any point with integers as both coordinates?
(A) y = x
(B) y = x + 1/2
(C) y = x + 5
(D) y = x*1/2
(E) y = x/2 + 5
Answer: B
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