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Can you help? - question from OG10th

This topic has 1 expert reply and 4 member replies
magical cook Master | Next Rank: 500 Posts Default Avatar
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Can you help? - question from OG10th

Post Fri Feb 02, 2007 9:19 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    The attached question's answer is E. Can anyone solve and explain?? (I am not good at math...)

    Thank you for your help!
    R.
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    Neo2000 Legendary Member
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    Post Sun Feb 04, 2007 1:53 am
    Put 4 in the Thousand's place

    Then the remaining 3 numbers can be arranged in 3! ways = 6
    So there are 6numbers of 4xxxx which means a min value of 24,000

    Similarly for 3 6x3 = 18000
    For 2 = 12,000
    For 1 = 6000

    So a minimum value of 24+18+12+6 = 60,000

    Remember that you still havent added the other numbers i.e. in the 4000 series you didnt add the value of 321 + 123+132+...

    So your final answer has to be E 66,660

    magical cook Master | Next Rank: 500 Posts Default Avatar
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    Post Sun Feb 04, 2007 2:22 am
    Thanks Neo for explaining it so clearly!

    I now fully understand Very Happy

    Thanks again.
    Rina

    Neo2000 Legendary Member
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    Post Sun Feb 04, 2007 2:30 am
    magical cook wrote:
    Thanks Neo for explaining it so clearly!

    Rina
    Aww shucks 'twas nothing

    Anytime Smile

    kandelaki Senior | Next Rank: 100 Posts Default Avatar
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    Post Fri Feb 23, 2007 1:16 am
    guys,

    i found another way of solving it...

    tell me if it is wrong, please

    so
    each combitation has 6 ways of starting with 1, 2, 3, 4
    if we multiply and then add just thousands- 6*2, 6*1, 6*3, 6*4, we get in sum 60,

    the D answer is 60000 but we know that it will be more than 60000 cause we just added the thousands and left hundreds tens etc
    so it has to be E.

    GMAT/MBA Expert

    Stacey Koprince GMAT Instructor
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    Post Mon Feb 26, 2007 11:04 pm
    kandelaki - that's the most efficient way to do it - nice job!

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