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Can you help? - question from OG10th

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magical cook Master | Next Rank: 500 Posts Default Avatar
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Can you help? - question from OG10th

Post Fri Feb 02, 2007 9:19 pm
The attached question's answer is E. Can anyone solve and explain?? (I am not good at math...)

Thank you for your help!
R.
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Stacey Koprince GMAT Instructor
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Post Mon Feb 26, 2007 11:04 pm
kandelaki - that's the most efficient way to do it - nice job!

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kandelaki Senior | Next Rank: 100 Posts Default Avatar
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Post Fri Feb 23, 2007 1:16 am
guys,

i found another way of solving it...

tell me if it is wrong, please

so
each combitation has 6 ways of starting with 1, 2, 3, 4
if we multiply and then add just thousands- 6*2, 6*1, 6*3, 6*4, we get in sum 60,

the D answer is 60000 but we know that it will be more than 60000 cause we just added the thousands and left hundreds tens etc
so it has to be E.

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Neo2000 Legendary Member
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Post Sun Feb 04, 2007 2:30 am
magical cook wrote:
Thanks Neo for explaining it so clearly!

Rina
Aww shucks 'twas nothing

Anytime Smile

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magical cook Master | Next Rank: 500 Posts Default Avatar
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Post Sun Feb 04, 2007 2:22 am
Thanks Neo for explaining it so clearly!

I now fully understand Very Happy

Thanks again.
Rina

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Neo2000 Legendary Member
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Post Sun Feb 04, 2007 1:53 am
Put 4 in the Thousand's place

Then the remaining 3 numbers can be arranged in 3! ways = 6
So there are 6numbers of 4xxxx which means a min value of 24,000

Similarly for 3 6x3 = 18000
For 2 = 12,000
For 1 = 6000

So a minimum value of 24+18+12+6 = 60,000

Remember that you still havent added the other numbers i.e. in the 4000 series you didnt add the value of 321 + 123+132+...

So your final answer has to be E 66,660

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