Burger King

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GMATSUCKER
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Topic: Burger King

Fri Mar 12, 2010 12:10 pm

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Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase
26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 9*2 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ?

a)13

b)27

c)37

d)83

e)None of these
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harsh001
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Fri Mar 12, 2010 9:20 pm

83 = (420 + 3) - Does not satisfy condition 83 = (99 + 1) - Does not satisfy condition 83 = (6*13 + 5) - Does not satisfy condition Thus in my view 83 is the answer

thephoenix
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Fri Mar 12, 2010 9:43 pm

harsh001 wrote: 83 = (420 + 3) - Does not satisfy condition 83 = (99 + 1) - Does not satisfy condition 83 = (613 + 5) - Does not satisfy condition Thus in my view 83 is the answer 97=63+20=83

Phirozz
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Fri Mar 12, 2010 10:24 pm

GMATSUCKER wrote: Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase 26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 92 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ? a)13 b)27 c)37 d)83 e)None of these 83 = 97+20 though 37 cannot be purchased its not the answer because even 40 which is greater than 37 cannot be purchased. So answer is E(none of these) only way to solve is thru options

thephoenix
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Fri Mar 12, 2010 10:29 pm

Phirozz wrote: GMATSUCKER wrote: Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase 26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 92 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ? a)13 b)27 c)37 d)83 e)None of these 83 = 97+20 though 37 cannot be purchased its not the answer because even 40 which is greater than 37 cannot be purchased. So answer is E(none of these) only way to solve is thru options 40 can be purchase in 20*2=40

Phirozz
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Sat Mar 13, 2010 1:20 am

thephoenix wrote: Phirozz wrote: GMATSUCKER wrote: Q: At Burger King , burgers can be bought in quantities of either 6 , 9 or 20 only . For example, one can purchase 26 (20 + 6) , 15 ( 6 + 9 ) and 24 ( 92 + 6) etc ,but can't purchase 10 burgers i.e without any lot. What is the largest number of burgers that can NOT be purchased ? a)13 b)27 c)37 d)83 e)None of these 83 = 97+20 though 37 cannot be purchased its not the answer because even 40 which is greater than 37 cannot be purchased. So answer is E(none of these) only way to solve is thru options 40 can be purchase in 20*2=40 ohh silly mistakes thanx bro anyway 43 cannot be purchased so ans remain same as E

GMATSUCKER
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Sat Mar 13, 2010 4:16 am

OAE. I don't have an explanation to this problem , so I made a guess that there are other possible combinations greater than the given options that cannot be purchased. But I would like to have other people's explanations for the answer E. _________________ GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT, GMAT What's life without GMAT !!!!!!!!

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Sat Mar 13, 2010 12:37 pm

GMATSUCKER wrote: OAE. I don't have an explanation to this problem , so I made a guess that there are other possible combinations greater than the given options that cannot be purchased. But I would like to have other people's explanations for the answer E. What could be the other possible explanations ? I am curious ? _________________ I want to win an OSCAR on the GMAT !!!

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Sat Mar 13, 2010 1:04 pm

STEVEN SPIELBERG wrote: What could be the other possible explanations ? I am curious ? Yes, I would also like to know, whether there could be any other possible explanation ? _________________ 800