A bicyclist travels uphill from town A to town B for 2 hours at an average speed of 4 miles per hour and returns along the same road at an average speed of 6 miles per hour. What is the bicyclist's average speed for the round trip, in miles per hour?
1) 4 4/5
2)5
3)5 1/5
4)5 2/5
5)5 3/5
Bicyclist's average speed
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Last edited by bhumika.k.shah on Sun Jan 31, 2010 4:19 am, edited 1 time in total.
- sars72
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i thought i knew how to solve these problems, but my answer is not among the answer choices . Please point out where i am going wrong.
Total Distance Traveled going up = 4*2 = 8 = Same distance traveled coming down
Time taken going up = 2 hrs
Time taken coming down = distance/speed= 8/6 = 4/3 hrs
Average Speed = Total Distance/ Total Time = 16/(4/3 + 2) = 16/(10/3) = 16*3/10 = 48/10 = 24/5
24/5 is not among the answer choices
I tried the same using the harmonic mean formula
harmonic mean
average speed = 2xy/(x+y), where x and y are the two speeds
--> average speed = (2*4*6)/(4+6) = 48/10 = 24/5
Please help!!
Total Distance Traveled going up = 4*2 = 8 = Same distance traveled coming down
Time taken going up = 2 hrs
Time taken coming down = distance/speed= 8/6 = 4/3 hrs
Average Speed = Total Distance/ Total Time = 16/(4/3 + 2) = 16/(10/3) = 16*3/10 = 48/10 = 24/5
24/5 is not among the answer choices
I tried the same using the harmonic mean formula
harmonic mean
average speed = 2xy/(x+y), where x and y are the two speeds
--> average speed = (2*4*6)/(4+6) = 48/10 = 24/5
Please help!!
- ajith
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Total distance between A&B = 8miles (4*2)bhumika.k.shah wrote:A bicyclist travels uphill from town A to town B for 2 hours at an average speed of 4 miles per hour and returns along the same road at an average speed of 6 miles per hour. What is the bicyclist's average speed for the round trip, in miles per hour?
A.4*4/5
B.5
C.5*1/5
D.5*2/5
E.5*3/5
I am too bad at this topic!
Time taken for the return trip = 8/6 = 4/3 hours
now average speed = total distance/total time = 16/(2+4/3) = 48/10 = 4&4/5 {answer choices have a mistake]
Always borrow money from a pessimist, he doesn't expect to be paid back.
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Edited.Got it wrong the second time also
ajith wrote:Total distance between A&B = 8miles (4*2)bhumika.k.shah wrote:A bicyclist travels uphill from town A to town B for 2 hours at an average speed of 4 miles per hour and returns along the same road at an average speed of 6 miles per hour. What is the bicyclist's average speed for the round trip, in miles per hour?
A.4*4/5
B.5
C.5*1/5
D.5*2/5
E.5*3/5
I am too bad at this topic!
Time taken for the return trip = 8/6 = 4/3 hours
now average speed = total distance/total time = 16/(2+4/3) = 48/10 = 4&4/5 {answer choices have a mistake]
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Hey
i know i m not really good at this. but i did the same thing what u did and got my answer as 24/5
Which is option A
P.s.: whats this harmonic mean formula and when can u use it ???
i know i m not really good at this. but i did the same thing what u did and got my answer as 24/5
Which is option A
P.s.: whats this harmonic mean formula and when can u use it ???
sars72 wrote:i thought i knew how to solve these problems, but my answer is not among the answer choices . Please point out where i am going wrong.
Total Distance Traveled going up = 4*2 = 8 = Same distance traveled coming down
Time taken going up = 2 hrs
Time taken coming down = distance/speed= 8/6 = 4/3 hrs
Average Speed = Total Distance/ Total Time = 16/(4/3 + 2) = 16/(10/3) = 16*3/10 = 48/10 = 24/5
24/5 is not among the answer choices
I tried the same using the harmonic mean formula
harmonic mean
average speed = 2xy/(x+y), where x and y are the two speeds
--> average speed = (2*4*6)/(4+6) = 48/10 = 24/5
Please help!!
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got it.how simple can it be.
Any link where speed,time & distance sums are consolidated into one file???
That would be of great help.!
Any link where speed,time & distance sums are consolidated into one file???
That would be of great help.!
bhumika.k.shah wrote:Edited.Got it wrong the second time also
ajith wrote:Total distance between A&B = 8miles (4*2)bhumika.k.shah wrote:A bicyclist travels uphill from town A to town B for 2 hours at an average speed of 4 miles per hour and returns along the same road at an average speed of 6 miles per hour. What is the bicyclist's average speed for the round trip, in miles per hour?
A.4*4/5
B.5
C.5*1/5
D.5*2/5
E.5*3/5
I am too bad at this topic!
Time taken for the return trip = 8/6 = 4/3 hours
now average speed = total distance/total time = 16/(2+4/3) = 48/10 = 4&4/5 {answer choices have a mistake]
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Basically,in speed-time-distance ques. 2 are constants and 1 is the variable.....the important part lies in identifying them.....
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I think the 1st answer 4 4/5 is correct.......................4 4/5 can be alternatively written as 48/10 or 24/5(the answer which you had got -bhumika)
- harsh.champ
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I have seen many people have developed fear regarding the SDT(Speed Distance Time) questions.......that does hinder your thought process......just believe in yourself ,identify the constants and the variables and it will seem easy to you.....its people's psychology not their ability that restricts them from solving the problems....
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thanks
harsh.champ wrote:I have seen many people have developed fear regarding the SDT(Speed Distance Time) questions.......that does hinder your thought process......just believe in yourself ,identify the constants and the variables and it will seem easy to you.....its people's psychology not their ability that restricts them from solving the problems....
- harsh.champ
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_________________bhumika.k.shah wrote:thanks
harsh.champ wrote:I have seen many people have developed fear regarding the SDT(Speed Distance Time) questions.......that does hinder your thought process......just believe in yourself ,identify the constants and the variables and it will seem easy to you.....its people's psychology not their ability that restricts them from solving the problems....
anytime...actually i also said this from my personal experience.............sometimes after i retrospect i find that it was my mind only that was creating the ceiling....not my ability..