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Register now and save up to $200 Available with Beat the GMAT members only code • Free Trial & Practice Exam BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • 1 Hour Free BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code batteries (OG) tagged by: Brent@GMATPrepNow This topic has 4 expert replies and 2 member replies razorback Junior | Next Rank: 30 Posts Joined 29 Aug 2011 Posted: 28 messages Thanked: 1 times batteries (OG) Mon Sep 19, 2011 5:20 pm Elapsed Time: 00:00 • Lap #[LAPCOUNT] ([LAPTIME]) A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold? (A) 3q/200 (read: 3q all over 200) (B) 3q/2 (read: 3q all over 2) (C) 150q (D) q/100 + 50 (read q over 100, then add 50) (E) 150/q Official answer soon. This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out. Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums! GMAT/MBA Expert Anurag@Gurome GMAT Instructor Joined 02 Apr 2010 Posted: 3835 messages Followed by: 518 members Thanked: 1852 times GMAT Score: 770 Mon Sep 19, 2011 7:02 pm razorback wrote: A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold? (A) 3q/200 (read: 3q all over 200) (B) 3q/2 (read: 3q all over 2) (C) 150q (D) q/100 + 50 (read q over 100, then add 50) (E) 150/q Official answer soon. This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out. Cost of 100 batteries =$q
Cost of 1 battery = \$ (q/100)
It is given that the selling price of 1 battery is 50 percent above the original cost per battery, so the selling price of 1 battery = (q/100) + (q/100)*(50/100) = (q/100) + (q/200) = 3q/200

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Mon Sep 19, 2011 7:21 pm
razorback wrote:
A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

(A) 3q/200 (read: 3q all over 200)
(B) 3q/2 (read: 3q all over 2)
(C) 150q
(E) 150/q

This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
Let q = 200.
Thus, 100 batteries were bought for a total cost of 200.
Cost per battery = 200/100 = 2.
Selling price = 2 + .5(2) = 3. This is our target.

Now we plug q=200 into the answers to see which yields our target of 3.

3q/200 = (3*200)/200 = 3.

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razorback Junior | Next Rank: 30 Posts
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Thu Sep 22, 2011 7:01 pm
Ok that makes a lot of sense, thanks.

leumas Senior | Next Rank: 100 Posts
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Fri Sep 23, 2011 8:14 am
razorback wrote:
A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

(A) 3q/200 (read: 3q all over 200)
(B) 3q/2 (read: 3q all over 2)
(C) 150q
(E) 150/q

This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
Cost = q/100
Profit =50%
Selling price=1.5q/100
Answer doesn't have this option: Multiply by 2.

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Scott@TargetTestPrep GMAT Instructor
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Wed Jun 24, 2015 3:16 am
razorback wrote:
A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

(A) 3q/200 (read: 3q all over 200)
(B) 3q/2 (read: 3q all over 2)
(C) 150q
(E) 150/q

This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
Solution:

We are given that 100 batteries cost a TOTAL of q dollars. We are also given that EACH battery was sold at 50% above the original cost. The first thing we must do is create an equation for q. Remember that q is the TOTAL COST. So if we make b = the original cost per battery we can say:

100 x b = q

b = q/100

We now have the original cost per battery in terms of q. Next, we determine the selling price when we increase the cost by 50%. To calculate this increase we simply multiply q/100 by 1.5. We have:

(q/100) x 1.5

(q/100) x 3/2 = 3q/200

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