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batteries (OG)

This topic has 4 expert replies and 2 member replies
razorback Junior | Next Rank: 30 Posts Default Avatar
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batteries (OG)

Post Mon Sep 19, 2011 5:20 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

    (A) 3q/200 (read: 3q all over 200)
    (B) 3q/2 (read: 3q all over 2)
    (C) 150q
    (D) q/100 + 50 (read q over 100, then add 50)
    (E) 150/q

    Official answer soon.

    This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.

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    Anurag@Gurome GMAT Instructor
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    Post Mon Sep 19, 2011 7:02 pm
    razorback wrote:
    A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

    (A) 3q/200 (read: 3q all over 200)
    (B) 3q/2 (read: 3q all over 2)
    (C) 150q
    (D) q/100 + 50 (read q over 100, then add 50)
    (E) 150/q

    Official answer soon.

    This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
    Cost of 100 batteries = $q
    Cost of 1 battery = $ (q/100)
    It is given that the selling price of 1 battery is 50 percent above the original cost per battery, so the selling price of 1 battery = (q/100) + (q/100)*(50/100) = (q/100) + (q/200) = 3q/200

    The correct answer is A.

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    Post Mon Sep 19, 2011 7:21 pm
    razorback wrote:
    A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

    (A) 3q/200 (read: 3q all over 200)
    (B) 3q/2 (read: 3q all over 2)
    (C) 150q
    (D) q/100 + 50 (read q over 100, then add 50)
    (E) 150/q

    Official answer soon.

    This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
    Let q = 200.
    Thus, 100 batteries were bought for a total cost of 200.
    Cost per battery = 200/100 = 2.
    Selling price = 2 + .5(2) = 3. This is our target.

    Now we plug q=200 into the answers to see which yields our target of 3.

    Only answer choice A works:
    3q/200 = (3*200)/200 = 3.

    The correct answer is A.

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    razorback Junior | Next Rank: 30 Posts Default Avatar
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    Post Thu Sep 22, 2011 7:01 pm
    Ok that makes a lot of sense, thanks.

    leumas Senior | Next Rank: 100 Posts
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    Post Fri Sep 23, 2011 8:14 am
    razorback wrote:
    A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

    (A) 3q/200 (read: 3q all over 200)
    (B) 3q/2 (read: 3q all over 2)
    (C) 150q
    (D) q/100 + 50 (read q over 100, then add 50)
    (E) 150/q

    Official answer soon.

    This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
    Cost = q/100
    Profit =50%
    Selling price=1.5q/100
    Answer doesn't have this option: Multiply by 2.

    3q/200= Answer

    GMAT/MBA Expert

    Post Wed Jun 24, 2015 3:16 am
    razorback wrote:
    A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

    (A) 3q/200 (read: 3q all over 200)
    (B) 3q/2 (read: 3q all over 2)
    (C) 150q
    (D) q/100 + 50 (read q over 100, then add 50)
    (E) 150/q

    Official answer soon.

    This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
    Solution:

    We are given that 100 batteries cost a TOTAL of q dollars. We are also given that EACH battery was sold at 50% above the original cost. The first thing we must do is create an equation for q. Remember that q is the TOTAL COST. So if we make b = the original cost per battery we can say:

    100 x b = q

    b = q/100

    We now have the original cost per battery in terms of q. Next, we determine the selling price when we increase the cost by 50%. To calculate this increase we simply multiply q/100 by 1.5. We have:

    (q/100) x 1.5

    (q/100) x 3/2 = 3q/200

    Answer: A

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