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Area Sector

This topic has 3 expert replies and 2 member replies
heshamelaziry Legendary Member Default Avatar
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Area Sector

Post Sat Nov 28, 2009 9:23 pm
The area of a certain circle is 8 times the area of a sector of the circle. What is the perimeter of the sector ?

A- The circumference of the circle is 12Pi.

B- The area of the sector is 9Pi/2

OA D

How to solve this considering the 2 equations:

Area of a sector = (central angle/360) *PiR^2

Length of sector arc = (central angle/ 360) * 2Pi r


Please be detailed.

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Post Sun Nov 29, 2009 2:56 pm
adam15 wrote:
I was wondering if the sector area is another circle with different radius, do still getting the same result. A is sufficient, because I consider the sector as a unite circle.and i am getting (6/sqr(2))*2.
Think of a circle as a pizza and a sector as a slice.

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adam15 Senior | Next Rank: 100 Posts Default Avatar
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Post Sun Nov 29, 2009 10:51 am
I was wondering if the sector area is another circle with different radius, do still getting the same result. A is sufficient, because I consider the sector as a unite circle.and i am getting (6/sqr(2))*2.

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Stuart Kovinsky GMAT Instructor
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Post Sat Nov 28, 2009 11:48 pm
heshamelaziry wrote:
why 12Pi = 8 (arc length) ? i understood from your post that sector areas and arc lenghts are proportional to the circle area, but I do not understand the concept. Could you please elaborate a bit more on this concept relevant to 12Pi = 8(arc length) ?


Thank you
It goes back to the original ratio:

(sector area)/(area of circle) = (arc length)/circumference

This ratio acknowledges that when we create a sector of the circle, we're simply dividing the area and circumference by the same amount.

For example, if we create 4 sectors, each with a central angle of 90 degrees, each sector will contain 1/4 the area of the circle and the arc length along the edge of each sector will be 1/4 of the circumference.

We know that for this circle:

(sector area)/(area of circle) = 1/8, so we simply sub in to get:

1/8 = (arc length)/circumference

and after cross multiplying:

circumference = 8(arc length)

Since we solved for circumference = 12pi, we sub in to get:

12pi = 8(arc length)

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heshamelaziry Legendary Member Default Avatar
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Post Sat Nov 28, 2009 10:34 pm
why 12Pi = 8 (arc length) ? i understood from your post that sector areas and arc lenghts are proportional to the circle area, but I do not understand the concept. Could you please elaborate a bit more on this concept relevant to 12Pi = 8(arc length) ?


Thank you

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Post Sat Nov 28, 2009 10:14 pm
heshamelaziry wrote:
The area of a certain circle is 8 times the area of a sector of the circle. What is the perimeter of the sector ?

A- The circumference of the circle is 12Pi.

B- The area of the sector is 9Pi/2

We know that everything about sectors of circles is proportional. We have the general circle sector ratio:

(degree measure of sector)/360 = (arc length of sector)/circumference = (area of sector)/(area of circle)

From the original, we know that (area of sector)/(area of circle) = 1/8; therefore, we can figure out the degrees of the arc (360/8) and the relationship between the arc length and the circumference (1:8).

What we're missing right now is a measurement - our circle could be tiny or could be huge.

The GMAT loves to test circles in data sufficiency, because if you know 1 concrete measurement you automatically know all the others; if you know 1 of radius, diameter, circumference or area, you know the entire circle.

So, we need pretty much any concrete measurement, keeping in mind that the perimeter of the sector is r + r + arc length of the sector.

(1) circumference = 12pi. Perfect, we can calculate radius and the arc length of the sector: sufficient.

(2) area of the sector = 9pi/2. Perfect, we can calculate the area of the entire circle, then the radius, then the circumference, then the arc length of the sector: sufficient.

Each statement is sufficient alone: choose D.

* * *

Based on your question, it looks like you want to see the calculations as well. We'd never need (or want) to do so on a DS question, but here you go:

(1) 2(pi)r = 12pi
r = 6
12pi = 8(arc length)
1.5pi = arc length

perimeter of sector = 2r + arc length = 12 + 1.5pi

(2) area of the sector = 9pi/2
area of circle = 8(9pi/2) = 36pi
36pi = pi(r^2)
36 = r^2
6 = r
circumference of circle = 2pi(r) = 12pi
12pi = 8(arc length)
1.5pi = arc length

perimeter of sector = 2r + arc length = 12 + 1.5pi

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