Answers to GMATPrep

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Answers to GMATPrep

by DMac » Mon Oct 23, 2006 4:04 pm
Has anyone seen the answers to the GMAT Prep exams posted anywhere? I can't figure out how to solve a couple of the problems I got wrong! Thanks.

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by beatthegmat » Wed Oct 25, 2006 3:35 pm
I don't think you are going to find these answers easily. I believe that the only time you can view the answers/explanations to GMATPrep exams is immediately after taking the test. Once you close the software, there isn't a way to go back to your previous test and review the answers/explanations.

It's been a while since I've used the software. Anyone else have thoughts?
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by DMac » Wed Oct 25, 2006 3:58 pm
The program will actually save your results, but it doesn't feature any explanations.

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by beatthegmat » Wed Oct 25, 2006 4:01 pm
Gotcha--thanks for clarifying.

Yes, you are likely going to have a hard time finding those explanations. If you are stuck in solving a few problems, I recommend posting them here and the community can help you.

Best of luck!
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Re: GMATprep questions

by sankruth » Thu Nov 29, 2007 10:08 am
k2 wrote:I took the GMAT prep exam and got 700 but I did get stumped by some easy questions and from looking at the answers still cant figure out how they got there so any help would be appreciated:

what is the greatest prime factor of 4^17- 2^28?

a)2
b)3
c)5
d)7
e)11

Five pieces of wood have an average (arithmetic mean) of length of 124 cm and a median length of 140 cm. what is the max possible length, in com, of the shortest piece of wood?

a) 90
b) 100
c) 110
d) 130
e) 140
1) 4^17 - 2^28 = (2^2)^17 -2^28
=2^34 - 2^28
=2^28.2^6 - 2^28
=2^28(2^6-1)
=2^28(63)

Greatest prime factor of 2^28 is 2, and of 63 is 7.

So D

2) Can be done by substituting answer choices. Start with C

110+ _ + 140 + _ + _ = 124.5 = 620

3 pieces must add up to 620 - 250 = 370

2nd piece can be between 110 and 140 (both inclusive).

If 2nd piece is 110, then one of the other two pieces will be less than 140. So 1st piece must be less 110

Choose B

100 + _ + 140 + _ + _ = 620

or 3 pieces add up to 380. If 2nd piece is 100, the other two pieces can be 140.

So option B.

Am I correct? This was very tricky and Im still not very confident with my answer :?

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by sirikesav » Thu Nov 29, 2007 10:24 am
the second question can be answered as follows


Total length = 124 * 5 = 620

Median = 140
hence 2 values below 140 and 2 above 140
Let us take the Minimum values for the values above 140 as we need Maximum value below 140
so they can be = 141,142

so remaining is 197.the maximum value can be 98.5

hence the possible Maximum value that is available is 90.

Please correct me if it is wrong

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by sirikesav » Thu Nov 29, 2007 10:30 am
sorry there was a mistake the values can be equal to 140, so remaining is 200 and the Maximum value is 100


So I go with option B

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by beatthegmat » Thu Nov 29, 2007 6:52 pm
In the future, please post these questions in the appropriate forum areas: Problem Solving, Data Sufficiency.

Thanks!
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