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An airport conveyor belt is 120 meters long. . .

This topic has 1 expert reply and 2 member replies

An airport conveyor belt is 120 meters long. . .

Post Wed Sep 20, 2017 7:56 am
An airport conveyor belt is 120 meters long, and moves at a constant rate of 2m/s. A man carrying two suitcases walks at a constant rate of 4m/s. How long will it take him to cross from one end of the conveyor belt to the other, if the man only walks for half the time he is on the conveyor belt?

A) 25 seconds
B) 30 seconds
C) 42 seconds
D) 45 seconds
E) 54 seconds

The OA is B.

Can anybody explain this PS question to me? If you could make a graph it would be better. Thank you.

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pannalal Junior | Next Rank: 30 Posts Default Avatar
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Post Fri Sep 22, 2017 1:51 am
Arithmetic Solution:
If man is walking on conveyor belt, his speed is 6 m per second (4m + 2m) whereas if he just stands on the conveyor, his speed is 2 m per second. As the man walks for half the time on the conveyor belt, the average speed is 4 m per second. So, total time taken to cover 120 meters is 120/4 = 30 seconds. Answer (C)

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pannalal Junior | Next Rank: 30 Posts Default Avatar
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Post Thu Sep 21, 2017 11:17 pm
If man is walking on conveyor belt, his speed is 6 m per second (4m + 2m) whereas if he just stands on the conveyor, his speed is 2 m per second. Assuming that he takes, total 'n' seconds. Then,

6n/2 + 2n/2 = 120
or 3n + n = 120
or 4n = 120
or n = 30.

Thus, answer is 30 seconds. So, the correct option is (B).

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pannalal Junior | Next Rank: 30 Posts Default Avatar
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Post Fri Sep 22, 2017 1:51 am
Arithmetic Solution:
If man is walking on conveyor belt, his speed is 6 m per second (4m + 2m) whereas if he just stands on the conveyor, his speed is 2 m per second. As the man walks for half the time on the conveyor belt, the average speed is 4 m per second. So, total time taken to cover 120 meters is 120/4 = 30 seconds. Answer (C)

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