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umaa Really wants to Beat The GMAT!
Joined: 08 Jun 2008 Posts: 177
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Posted: Thu Jul 17, 2008 1:36 am Post subject: Amusement park |
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In an amusement park there’s a fishing mini-game. There are fish numbered 201 to 450. If I fish out one fish randomly, what’s the probability that the ticket selected at random will have a hundreds digit of 4, which will win me a cool prize?
a. 50/250
b. 49/250
c. 1/4
d. 1/5
e. 2/5
Answer: d |
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sudhir3127 Moderator
Joined: 07 Jul 2008 Posts: 818
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Location: INDIA Target GMAT Score: 700+
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Posted: Thu Jul 17, 2008 2:00 am Post subject: |
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whats the difference between option A and D
i am getting it as 51/250 |
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umaa Really wants to Beat The GMAT!
Joined: 08 Jun 2008 Posts: 177
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Posted: Thu Jul 17, 2008 2:16 am Post subject: |
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right. the first one might be, 51/250. I'm getting 61/250.
First and Last possible numbers:
(444-204)/4 = 240/4 = 60 + 1 = 61
Probability would be, 61/250.
Please let me know what i'm doing wrong |
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parallel_chase GMAT Titan
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Target GMAT Score: V50
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Posted: Thu Jul 17, 2008 2:21 am Post subject: |
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| sudhir3127 wrote: | whats the difference between option A and D
i am getting it as 51/250 |
i am also getting 51/250 |
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parallel_chase GMAT Titan
Joined: 20 Jun 2007 Posts: 1153
Thanks given: 19 Thanked 115 times in 108 posts
Target GMAT Score: V50
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Posted: Thu Jul 17, 2008 2:24 am Post subject: |
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| umaa wrote: | right. the first one might be, 51/250. I'm getting 61/250.
First and Last possible numbers:
(444-204)/4 = 240/4 = 60 + 1 = 61
Probability would be, 61/250.
Please let me know what i'm doing wrong |
First number is 400 last number is 450
450-400= 50 +1 = 51
450-201= 249 +1=250
51/250 |
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