If a > 0, b>0, and c>0, is a(b-c) = 0?
1) b-c = c-b
2) b/c = c/b
Algebraic expression - D
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this is a data sufficiency question right?
1) b-c=c-b -> 2b=2c -> b=c, then b-c=0, so it's sufficient.
2) b/c=c/b -> b^2=c^2, since both b and c > 0 this also means that b=c, also sufficient, answer D.
1) b-c=c-b -> 2b=2c -> b=c, then b-c=0, so it's sufficient.
2) b/c=c/b -> b^2=c^2, since both b and c > 0 this also means that b=c, also sufficient, answer D.
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tanyajoseph wrote:If a > 0, b>0, and c>0, is a(b-c) = 0?
1) b-c = c-b
2) b/c = c/b
Shouldnt the answer be A
Correct me if am wrong.
As 2nd cond says
b^2 = c^2
b^2 - c^2 =0
(b-c)(b+c)= 0
b=c or b=-c
and if b=-c then a(b-c) is not equal to 0
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blah45 wrote:b>0 and c > 0, so b=-c will NOT hold true.jaspreet.sharma wrote:
and if b=-c then a(b-c) is not equal to 0
Thus, my answer is D.
Oh thanks for correcting me ....i missed that part.....