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Airplanes A and B traveled the same 360-mile route...

This topic has 2 expert replies and 0 member replies

Airplanes A and B traveled the same 360-mile route...

Post Fri Nov 03, 2017 9:29 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was 1/3 slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?

    (A) 2

    (B) 2(1/3)

    (C) 2(1/2)

    (D) 2(2/3)

    (E) 3

    The OA is E.

    I don't understand why that is the correct answer. Please can any expert explain this PS question for me? Thanks.

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    Post Fri Nov 03, 2017 9:53 am
    LUANDATO wrote:
    Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was 1/3 slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?

    (A) 2

    (B) 2(1/3)

    (C) 2(1/2)

    (D) 2(2/3)

    (E) 3

    The OA is E.

    I don't understand why that is the correct answer. Please can any expert explain this PS question for me? Thanks.
    Time and rate have a reciprocal relationship. For example, if you run twice as fast I do, you'd cover the same distance in 1/2 the time. If you ran 4/3 as fast as I did, you'd cover the same distance in 3/4 the time, etc.

    If plane B's rate is 1/3 less than A's rate, then B's rate is 2/3 of A's rate.
    If B's rate is 2/3 of A's rate, then it covers the same distance in 3/2 the time. If A did the trip in 2 hours, then B did it in (3/2)*2 = 3 hours. The answer is E.

    (Note that the actual distance doesn't matter here. What's relevant is that each plane traveled the same distance.)

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    Post Sun Nov 05, 2017 12:24 pm
    Hi LUANDATO,

    David's explanation about the relationship between Rate and Time is spot-on. If you don't realize how that relationship applies in these types of questions, then you can still answer this question with some basic arithmetic.

    We're told that Airplane A traveled a 360-mile route in 2 hours. Thus, it traveled at 360/2 = 180 miles per hour.

    We're also told that Airplane B traveled the SAME distance at an average speed that was 1/3 SLOWER than the average speed of airplane A. One third of 180 is 60, so Airplane B traveled at 180 - 60 = 120 miles per hour.

    We're asked for the number of hours that it took Airplane B to travel the route....
    Distance = (Rate)(Time)
    360 miles = (120 mi/hour)(T)
    360/120 = T
    3 hours = T

    Final Answer: E

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