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A pizza with diameter of 12 inches is split into 8 equally s

This topic has 1 expert reply and 0 member replies

A pizza with diameter of 12 inches is split into 8 equally s

Post Wed Sep 20, 2017 4:19 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    A pizza with diameter of 12 inches is split into 8 equally sized pieces. (There is a figure here I cannot insert for some reason: imagine a circle with 8 points on the perimeter: A through H. The center is point "O"). 4 non-adjacent pieces are removed. What is the perimeter AOBCODEOFGOHA of the pizza now, including the inside edges of the slices?

    A) 48ππ+48

    B) 24ππ+48

    C) 24ππ+24

    D) 6ππ+48

    E) 6ππ+24

    OA: D
    Is there a strategic approach to this question?

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    Post Wed Sep 20, 2017 6:42 am
    ardz24 wrote:
    A pizza with diameter of 12 inches is split into 8 equally sized pieces. (There is a figure here I cannot insert for some reason: imagine a circle with 8 points on the perimeter: A through H. The center is point "O"). 4 non-adjacent pieces are removed. What is the perimeter AOBCODEOFGOHA of the pizza now, including the inside edges of the slices?

    A) 48ππ+48

    B) 24ππ+48

    C) 24ππ+24

    D) 6ππ+48

    E) 6ππ+24

    OA: D
    Is there a strategic approach to this question?
    If the diameter is 12, the full circumference of the circle would be 12π. Because half the pieces are removed, half the circumference remains, so we've got 6π.

    We've got four slices left, and the length of each edge of a slice will be the radius, or 6. Each of the 4 slices has two edges, giving us a total of 8 edges, each with a length of 6, for a total of 8*6 = 48.

    Total perimeter = 6π + 48. The answer is D

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