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A job opening was posted in September and again...

This topic has 2 expert replies and 0 member replies

A job opening was posted in September and again...

Post Tue Oct 31, 2017 9:20 am
A job opening was posted in September and again in January. In September, the number of applicants for the position was 60. What was the percent change in the number of applicants from September to January?

(1) The number of applicants in January was one-third the number of applicants in September
(2) The number of applicants in January was 20

The OA is D.

I need help with this DS question. Please, can any expert assist me with it? Thanks.

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Post Fri Nov 10, 2017 1:19 pm
To find the percentage change, all we need is the number of applicants in January. Once we have that, we can use the percent change formula: (New - Old)/Old * 100.

S1: gives us the number of applicants in January, sufficient
S2:: gives us the number of applicants in January, also sufficient!

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Thanked by: swerve
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Post Fri Nov 10, 2017 1:17 am
swerve wrote:
A job opening was posted in September and again in January. In September, the number of applicants for the position was 60. What was the percent change in the number of applicants from September to January?

(1) The number of applicants in January was one-third the number of applicants in September
(2) The number of applicants in January was 20

The OA is D.

I need help with this DS question. Please, can any expert assist me with it? Thanks.
The percent change in the number of applicants from September to January is given by

{[(# of applicants in Jan) - (# of applicants in Sept)] / (# of applicants in Sept)} *100% = {[(# of applicants in Jan) - 60] / 60} *100%

If we get # of applicants in Jan, we get the answer.

(1) The number of applicants in January was one-third the number of applicants in September.

=> # of applicants in Jan = 1/3 of 60 = 20. Sufficient

(2) The number of applicants in January was 20

Sufficient.

The correct answer: D

Hope this helps!

-Jay
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