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## A cube has a volume of 72. If it is divided into 8 equal cub

tagged by: Brent@GMATPrepNow

This topic has 2 expert replies and 1 member reply

### Top Member

ardz24 Master | Next Rank: 500 Posts
Joined
22 Aug 2017
Posted:
315 messages

#### A cube has a volume of 72. If it is divided into 8 equal cub

Wed Dec 06, 2017 6:05 am
A cube has a volume of 72. If it is divided into 8 equal cubes, the ratio of an edge of a smaller cube to an edge of the original cube is

(A) 1 : 2
(B) 1: 3
(C) 1 : 3âˆš2
(D) 2 : 9
(E) 1 : 9

I'm confused how to set up the formulas here. Can any experts help?

### GMAT/MBA Expert

EconomistGMATTutor GMAT Instructor
Joined
04 Oct 2017
Posted:
460 messages
Followed by:
10 members
180
Wed Dec 06, 2017 9:29 am
Quote:
A cube has a volume of 72. If it is divided into 8 equal cubes, the ratio of an edge of a smaller cube to an edge of the original cube is

(A) 1 : 2
(B) 1: 3
(C) 1 : 3âˆš2
(D) 2 : 9
(E) 1 : 9

I'm confused how to set up the formulas here. Can any experts help?
Hi ardz24,
Let's take a look at your question.

Volume of original cube = 72
Original cube is divided into 8 equal cubes, therefore, volume of each of the new cube will be:
$$=\frac{72}{8}=9$$

Let, edge length of original cube be 'x' and edge length of each of the new cubes is 'y', then,
$$x^3=72$$
$$y^3=9$$

Volume of new cube : Volume of Original cube
$$y^3\ :\ \ x^3 = 9\ :\ 72$$
$$y^3\ :\ \ x^3 =1\ :\ 8$$

But we are asked to find the ratio of an edge of a smaller cube to an edge of the original cube, i.e., x : y
$$y^3\ :\ \ x^3 =1\ :\ 8$$
$$y^3\ :\ \ x^3 =1^3\ :\ 2^3$$
$$y\ :\ \ x =1\ :\ 2$$

Therefore, Option A is correct.

Hope it helps.
I am available if you'd like any follow up.

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### GMAT/MBA Expert

Brent@GMATPrepNow GMAT Instructor
Joined
08 Dec 2008
Posted:
11211 messages
Followed by:
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GMAT Score:
770
Wed Dec 06, 2017 9:18 am
ardz24 wrote:
A cube has a volume of 72. If it is divided into 8 equal cubes, the ratio of an edge of a smaller cube to an edge of the original cube is

(A) 1 : 2
(B) 1: 3
(C) 1 : 3âˆš2
(D) 2 : 9
(E) 1 : 9
Great question!
The great thing about it is that the volume of the original cube is irrelevant.
It all comes down to what happens when we divide ANY cube into 8 equal cubes.
Here's what I mean.

Take a cube and divide it into 8 equal cubes...
ttps://postimg.org/image/5g2p6el9n/" target="_blank">

If we let x = the length of one edge of the ORIGINAL cube....
ttps://postimg.org/image/5g2p6f0p7/" target="_blank">

....then x/2 = the length of one edge of the SMALLER cube....
ttps://postimg.org/image/ik89j3l17/" target="_blank">

What is the ratio of an edge of a smaller cube to an edge of the original cube?
Get get: x/2 : x
Divide both sides by x to get the EQUIVALENT ratio: 1/2 : 1
Multiply both sides by 2 to get the EQUIVALENT ratio: 1 : 2

Cheers,
Brent

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### Top Member

GMATWisdom Master | Next Rank: 500 Posts
Joined
29 Nov 2017
Posted:
100 messages
14
Wed Dec 06, 2017 8:01 am
ardz24 wrote:
A cube has a volume of 72. If it is divided into 8 equal cubes, the ratio of an edge of a smaller cube to an edge of the original cube is

(A) 1 : 2
(B) 1: 3
(C) 1 : 3âˆš2
(D) 2 : 9
(E) 1 : 9

I'm confused how to set up the formulas here. Can any experts help?
If the size of the edge of original cube is = a, its volume would be = a^3
And if the size of the edge of new cube is =b, its volume would be = b^3
Then ratio of volume of the new cube to the volume of original cube would be b^3 : a^3
In the present case a^3=72 and b^3= 72/8 = 9
Therefore b^3 : a^3 = 9 : 72
Or b^3 : a^3 = 1 : 8
Taking cube root of both the sides we get
b : a = 1 : 2
hence A is the correct answer

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