Welcome! Check out our free B-School Guides to learn how you compare with other applicants.
Login or Register
 

500 ps test 22 test#15

This topic has 6 member replies
Bookmark
Previous Topic Next Topic
dunkin77 Really wants to Beat The GMAT! Default Avatar
Joined
01 Apr 2007
Posted:
269 messages
500 ps test 22 test#15 Post Sun Apr 15, 2007 11:27 am
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    Hi,

    I could not find an answer for this question but I think the answer is B) -- Can anyone please tell me B) is correct? Very Happy


    15. A certain used-book dealer sells paperback books at 3 times dealer's cost and hardback books at 4 times dealer's cost. Last week the dealer sold a total of 120 books, each of which had cost the dealer $1. If the gross profit (sales revenue minus dealer's cost) on the sale of all of these books was $300, how many of the books sold were paperbacks?
    (A) 40
    (B) 60
    (C) 75
    (D) 90
    (E) 100

    Need free GMAT or MBA advice from an expert? Register for Beat The GMAT now and post your question in these forums!
    jayhawk2001 Community Manager
    Joined
    28 Jan 2007
    Posted:
    789 messages
    Followed by:
    1 members
    Thanked:
    25 times
    Post Sun Apr 15, 2007 1:10 pm
    3p + 4(120-p) = 120 + 300
    p = 60

    dunkin77 Really wants to Beat The GMAT! Default Avatar
    Joined
    01 Apr 2007
    Posted:
    269 messages
    Post Sun Apr 15, 2007 2:28 pm
    Thank you Jay for your response.

    What I thought I did was...

    3P + 4H = 300
    P + H = 120

    3P+4(120-p)=300
    p=180???

    I thought I got B) but now I can't remember how I got p=60.

    Can you explain how come you add 120 to 300 ?

    Smile

    ns88 Rising GMAT Star Default Avatar
    Joined
    14 Apr 2007
    Posted:
    33 messages
    Post Sun Apr 15, 2007 3:15 pm
    paperback=x
    hardcover=y


    total books= 120=x+y

    total cost $120= 3x+4y

    total revenue= (3)($1)x+ 4($1)y= 3x+4y

    profit= 300 = (3x+4y)- 120

    or 420=3x +4y


    since 120= x+ y

    x=(120-y)

    420= [(3)(120-y) +4y]

    y=60

    x=60

    jayhawk2001 Community Manager
    Joined
    28 Jan 2007
    Posted:
    789 messages
    Followed by:
    1 members
    Thanked:
    25 times
    Post Sun Apr 15, 2007 3:33 pm
    dunkin77 wrote:
    Thank you Jay for your response.

    What I thought I did was...

    3P + 4H = 300
    P + H = 120

    3P+4(120-p)=300
    p=180???

    I thought I got B) but now I can't remember how I got p=60.

    Can you explain how come you add 120 to 300 ?

    Smile
    The question states that the difference between the revenus
    and the cost is 300. The cost is 120 * $1 = 120. Hence 120 + 300
    is the total sale price.

    dunkin77 Really wants to Beat The GMAT! Default Avatar
    Joined
    01 Apr 2007
    Posted:
    269 messages
    Post Sun Apr 15, 2007 7:16 pm
    Okay - thanks!!

    now I remember what I did...

    3p+4H - (p+H) = 300

    P+H = 120

    but yours is more efficient way!!

    Thank you!

    Cybermusings GMAT Destroyer! Default Avatar
    Joined
    27 Mar 2007
    Posted:
    559 messages
    Followed by:
    1 members
    Thanked:
    4 times
    Post Mon Apr 16, 2007 5:31 am
    Suppose the dealer sold x paperback books and y hardback books.
    x+y = 120 ---------- 1)
    3x+4y-120 = 300 ------- 2)
    Solving the 2 you'll get x = 60 books

    Best Conversation Starters
    1 vipulgoyal 32 topics
    2 hemant_rajput 23 topics
    3 guerrero 18 topics
    4 abhirup1711 17 topics
    5 sana.noor 16 topics
    See More Top Beat The GMAT Members...

    Most Active Experts
    1 image description Brent@GMATPrepNow

    GMAT Prep Now Teacher

    		 211 posts
    2 image description GMATGuruNY

    The Princeton Review Teacher

    		 137 posts
    3 image description Jim@StratusPrep

    Stratus Prep

    		 60 posts
    4 image description Jon@Admissionado

    Admissionado

    		 49 posts
    5 image description David@VeritasPrep

    Veritas Prep

    		 31 posts
    See More Top Beat The GMAT Experts