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500 PS

This topic has 2 member replies
dunkin77 Master | Next Rank: 500 Posts Default Avatar
Joined
01 Apr 2007
Posted:
269 messages

500 PS

Post Mon Apr 02, 2007 12:23 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    Hi,

    My answer to the attached question was B) but turned out that the correcr answer is A) - Could anyone please help?
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    vk.neni Junior | Next Rank: 30 Posts Default Avatar
    Joined
    27 Mar 2007
    Posted:
    12 messages
    Post Mon Apr 02, 2007 1:47 pm
    It appears that the above equations can be reorganized a bit to make it easy for the further processing:

    x = sqrt(4xy - 4y^2)

    x^2 = 4xy - 4y^2

    x^2 - 4xy + 4y^2 = 0

    (x-2y)^2 = 0

    x- 2y = 0

    x = 2y

    Answer is A

    Post Fri Sep 29, 2017 1:29 pm
    Given that x = sqrt(4xy - 4y^2)
    square both side, we have
    x^2 = 4xy - 4y^2
    The above equation can be rewritten as
    x^2 - 4xy - 4y^2= 0
    Mathematically,
    (x-2y)^2 = x^2 - 4xy - 4y^2
    we can rewrite (x-2y)^2=0
    square both side, we have x-2y = 0
    i.e eliminating the square at the left hand side of the equation.
    x-2y = 0
    x=2y

    option A is correct

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