| View previous topic :: View next topic |
| Author |
Message |
ajmoney09
Rising GMAT Star
Joined: 25 May 2008
Posts: 55
Thanks given: 0
Thanked 0 times in 0 posts
|
 Posted: Tue Aug 19, 2008 5:59 pm Post subject: 3 quick questions. |
 |
|
|
|
| Back to top |
|
 |
|
|
4meonly
GMAT Destroyer!
Joined: 16 Aug 2008
Posts: 666
Thanks given: 19
Thanked 14 times in 14 posts
Target GMAT Score: 750)
GMAT Score: 620(
|
| Posted: Tue Aug 19, 2008 11:35 pm Post subject: |
|
|
About question 3
I’ll mark even as E, odd – as O.
(1)
x(y+5) – even.
Means that
a. x and y+5 are both E, making y O
b. x-E, y+5=O, making y-E
c. x-O, y+5=E, making y O
x can be as O as E – INSUFFICIENT
(2)
6y^2+4y+25 = E
Means that 6y^2+4y = O
factorizing y we get y(6y+4) = O
6y+4 is obviously E, this means that y is O
But nothing about x….– INSUFFICIENT
(1) and (2)
From (2) we know that y is Even.
From (1) we know that to make x(y+5) even x can be as E (from a.) as O (from c.)
So, INSUFFICIENT
Answer is E.
Here E doesn’t mean Even 
|
|
| Back to top |
|
|
4meonly
GMAT Destroyer!
Joined: 16 Aug 2008
Posts: 666
Thanks given: 19
Thanked 14 times in 14 posts
Target GMAT Score: 750)
GMAT Score: 620(
|
| Posted: Tue Aug 19, 2008 11:44 pm Post subject: |
|
|
About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.
Thats why (2) in SUFFicient making B the right answer
About 2nd question - no idea, too 
|
|
| Back to top |
|
|
sharad
Just gettin' started!
Joined: 24 Jul 2008
Posts: 6
Thanks given: 0
Thanked 0 times in 0 posts
Test Date: 4-sept-08
|
| Posted: Wed Aug 20, 2008 12:58 am Post subject: |
|
|
Question 3
using 2)
The quadratic equation will be even under following condition
6y2 (always even) + 25 (odd) + 41y (this needs to be odd, hence y cannot be even)
So get y is odd
From 1) x(y+5)
y+5 is even hence even . (x, even or odd) will give x(y+5) as even
hence, even using both the statement you it is not possible to determine if x is odd or even hence E
|
|
| Back to top |
|
|
ajmoney09
Rising GMAT Star
Joined: 25 May 2008
Posts: 55
Thanks given: 0
Thanked 0 times in 0 posts
|
| Posted: Wed Aug 20, 2008 7:05 am Post subject: |
|
|
| 4meonly wrote: | About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.
Thats why (2) in SUFFicient making B the right answer
About 2nd question - no idea, too |
But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.
|
|
| Back to top |
|
|
|
|
ajmoney09
Rising GMAT Star
Joined: 25 May 2008
Posts: 55
Thanks given: 0
Thanked 0 times in 0 posts
|
| Posted: Wed Aug 20, 2008 7:07 am Post subject: |
|
|
| sharad wrote: | Question 3
using 2)
The quadratic equation will be even under following condition
6y2 (always even) + 25 (odd) + 41y (this needs to be odd, hence y cannot be even)
So get y is odd
From 1) x(y+5)
y+5 is even hence even . (x, even or odd) will give x(y+5) as even
hence, even using both the statement you it is not possible to determine if x is odd or even hence E |
Thanks for this. Made sense.
|
|
| Back to top |
|
|
ajmoney09
Rising GMAT Star
Joined: 25 May 2008
Posts: 55
Thanks given: 0
Thanked 0 times in 0 posts
|
| Posted: Wed Aug 20, 2008 7:08 am Post subject: |
|
|
| 4meonly wrote: | About question 3
I’ll mark even as E, odd – as O.
(1)
x(y+5) – even.
Means that
a. x and y+5 are both E, making y O
b. x-E, y+5=O, making y-E
c. x-O, y+5=E, making y O
x can be as O as E – INSUFFICIENT
(2)
6y^2+4y+25 = E
Means that 6y^2+4y = O
factorizing y we get y(6y+4) = O
6y+4 is obviously E, this means that y is O
But nothing about x….– INSUFFICIENT
(1) and (2)
From (2) we know that y is Even.
From (1) we know that to make x(y+5) even x can be as E (from a.) as O (from c.)
So, INSUFFICIENT
Answer is E.
Here E doesn’t mean Even |
Thanks man.
|
|
| Back to top |
|
|
4meonly
GMAT Destroyer!
Joined: 16 Aug 2008
Posts: 666
Thanks given: 19
Thanked 14 times in 14 posts
Target GMAT Score: 750)
GMAT Score: 620(
|
| Posted: Wed Aug 20, 2008 8:26 am Post subject: |
|
|
| ajmoney09 wrote: | | 4meonly wrote: | About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.
Thats why (2) in SUFFicient making B the right answer
About 2nd question - no idea, too |
But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1. |
Oh, yes, sorry
In general ,to make the total price 130 cents we have only one combination
Anybody with 2nd question? 
|
|
| Back to top |
|
|
ajmoney09
Rising GMAT Star
Joined: 25 May 2008
Posts: 55
Thanks given: 0
Thanked 0 times in 0 posts
|
| Posted: Wed Aug 20, 2008 5:50 pm Post subject: |
|
|
| 4meonly wrote: | | ajmoney09 wrote: | | 4meonly wrote: | About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.
Thats why (2) in SUFFicient making B the right answer
About 2nd question - no idea, too |
But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1. |
Oh, yes, sorry
In general ,to make the total price 130 cents we have only one combination
Anybody with 2nd question? |
For sure someone help with the second I was CONFUSED!
I am taking test on Friday....really nervous! 
|
|
| Back to top |
|
|
parallel_chase
GMAT Titan
Joined: 20 Jun 2007
Posts: 1153
Thanks given: 19
Thanked 115 times in 108 posts
Target GMAT Score: V50
|
| Posted: Wed Aug 20, 2008 6:28 pm Post subject: |
|
|
First of all dont be nervous. Its just one question, you have 37 different questions to face on quant.
from the question stem we can conclude:
500 is closer to x i.e. 400-600
400 is closer to y i.e. 300-500
Statement I
x < 500
x is closer to 400-499
we dont know anything about y. Insufficient.
Statement II
y < 400
y is closer to 300-399
we dont know anything about x. Insufficient.
Combining I & II
x is closer to 400-499
y is closer to 300-399
x+y = 400+300 = 700 x+y is closer to 700
or
x+y = 499+399 = 900 approx. is closer to 900
or that matter any values of x and y will give a range closer to either 700,800 or 900
Therefore Insufficient.
Hence E is the answer.
Let me know if you still have any doubts.
Good Luck!!!
|
|
| Back to top |
|
|
|
|
|
